It's possible to build a spiral with cascade. It's not difficult but it needs a good knowledge of the geometry and the topology in OCC. the principle is to build a line (L) 2d which describes the evolution of the Hight and the angle from the parameter of the line (w). x = H = Lx(w) , y = teta = Ly(w) We place this curve 2d in the parametric space of a cylinder. v = H; u = teta. we build the curve on surface defined by the line2d and the cylinder . C(w) = Cy(teta(w),H(w)); where Cy is the parametric equation of the cylinder.
the curve is now defined, after we make edge, face. and we can build the 3d definition of the curve.
Tue, 09/19/2000 - 11:26
Hello Anna;
It's possible to build a spiral with cascade. It's not difficult but it needs a good knowledge of the geometry and the topology in OCC. the principle is to build a line (L) 2d which describes the evolution of the Hight and the angle from the parameter of the line (w). x = H = Lx(w) , y = teta = Ly(w) We place this curve 2d in the parametric space of a cylinder. v = H; u = teta. we build the curve on surface defined by the line2d and the cylinder . C(w) = Cy(teta(w),H(w)); where Cy is the parametric equation of the cylinder.
the curve is now defined, after we make edge, face. and we can build the 3d definition of the curve.
regards
Yves
Tue, 09/19/2000 - 21:32
Thank you, Yves! I'll try that way. You've help me very much!
Thu, 02/08/2007 - 12:52
HI
Its been long time .. were u able to create a spiral (2d curve)
and helical curve ( as described above)
thanks for the answer in advance
PG
Thu, 02/08/2007 - 20:53
I would also be interested in some hints.
Best regards
Pawel